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Ionic Compounds

Mahi Tuatahi

Open your book to your table of ions. In groups (below), use your devices to find out the names of the ions of your column, and write the names on the board.

Copy the names of the ions into your book from the other groups!

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Ions

Ions are atoms that have gained or lost electrons in order to have a full valence shell.

Valence: outermost


Example

This is an oxygen atom. Copy the diagram into your book and give the electron shell configuration e.g. [2,3]

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Making an ion is like rounding:


Think again about the oxygen atom and answer these questions:

  1. Will it prefer to gain or lose electrons?
  2. How many electrons will it need to gain/lose to have a full outer shell?

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Copy this table into your own book and work in pairs to complete it.

Oxygen AtomOxygen Ion
Electron Shell Configuration
Number of Protons
Number of Electrons
Overall Charge

Oxygen AtomOxygen Ion
Electron Shell Configuration[2, 6][2, 8]2-
Number of Protons88
Number of Electrons810
Overall Charge02-

Writing Ions

\begin{aligned} O^{2-} \end{aligned}


Making Ionic Compounds

\begin{aligned} Na^{+} + Cl^{-} \rightarrow NaCl \
Cu^{2+} + 2OH^{-} \rightarrow Cu(OH)_{2} \end{aligned}


Game!

Your answer is simply to give the compound like this:

\begin{aligned} NaOH \end{aligned}


Compound One

Sodium iodide


Compound One

Sodium iodide: $NaI$


Compound Two

Silver iodide


Compound Two

Silver iodide: $AgI$


Compound Three

Lithium fluoride


Compound Three

Lithium fluoride: $LiF$


Compound Four

Ammonium chloride


Compound Four

Ammonium chloride: $NH_{4}CL$


Compound Five

Magnesium oxide


Compound Five

Magnesium oxide: $MgO$


Compound Six

Lead sulfate


Compound Six

Lead sulfate: $PbSO_{4}$


Compound Seven

Barium carbonate


Compound Seven

Barium carbonate: $BaCO_{3}$


Compound Eight

Zinc iodide


Compound Eight

Zinc iodide: $ZnI_{2}$


Compound Nine

Aluminium chloride


Compound Nine

Aluminium chloride: $AlCl_{3}$


Compound Ten

Aluminium nitrate


Compound Ten

Aluminium nitrate: $Al(NO_{3})_{3}$

Compound Eleven

Aluminium sulfate


Compound Eleven

Aluminium sulfate: $Al_{2}(SO_{4})_{3}$


Compound Twelve

Iron (II) oxide


Compound Twelve

Iron (II) oxide: $FeO$


Compound Thirteen

Iron (III) oxide


Compound Thirteen

Iron (III) oxide: $Fe_{2}O_{3}$


Compound Fourteen

Sodium bicarbonate


Compound Fourteen

Sodium bicarbonate: $NaHCO_{3}$


Compound Fifteen

Lead bicarbonate


Compound Fifteen

Lead bicarbonate: $Pb(HCO_{3})_{2}$

Game Answers

1-56-1011-15
$NaI$$PbSO_{4}$$Al_{2}(SO_{4})_{3}$
$AgI$$BaCO_{3}$$FeO$
$LiF$$ZnI_{2}$$Fe_{2}O_{3}$
$NHCl_{3}$$AlCl_{3}$$NaHCO_{3}$
$MgO$$Al(NO_{3})_{3}$$Pb(HCO_{3})_{2}$

Quizziz!

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Electron Transfer

Ionic compounds form because:

By giving/receiving electrons they form an ionic bond (electrostatic forces) and make a neutral compound.